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Find the absolute value of: sec (pi/7)+sec (3pi/7)+sec (5pi/7)

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4 months ago

```							Dear student Dear student cos(π/7) + cos(3π/7) + cos(5π/7)  Multuiply and divide by 2sin(π/7)  = 1/2sin(π/7) [ 2sin(π/7)cos(π/7) + 2sin(π/7)cos(3π/7) + 2sin(π/7)cos(5π/7) ]  Use the following  sin(2A) = 2sinAcosA  2sinAcosB = sin(A+B) + sin(A-B)  = 1/2sin(π/7) [ sin(2π/7) + sin(π/7+3π/7) + sin(π/7-3π/7) + sin(π/7+5π/7) + sin(π/7-5π/7) ]  = 1/2sin(π/7) [ sin(2π/7) + sin(4π/7) + sin(-2π/7) + sin(6π/7) + sin(-4π/7) ]  = 1/2sin(π/7) [ sin(2π/7) + sin(4π/7) - sin(2π/7) + sin(6π/7) - sin(4π/7) ]  = 1/2sin(π/7) [sin(6π/7)]  = 1/2sin(π/7) [sin(π - π/7)]  = [sin(π/7)]/2sin(π/7)  = 1/2
```
4 months ago
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