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Find all the possible values of x, yx, y not equal to zero such thatsec2A = 4xy/(x+y)^2

Kawal , 10 Years ago
Grade 11
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:Hello student, please find answer to your question
sec^{2}A = \frac{4xy}{(x+y)^{2}}
sec^{2}A \geq 1
\frac{4xy}{(x+y)^{2}}\geq 1
4xy\geq (x+y)^{2}
(x+y)^{2}-4xy \leq 0
(x-y)^{2} \leq 0
Only solution is
x = y
x, y\in R - (0)

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