0

Guest

Courses New

Excuse me sir/ mamThis que to fin minimum value...Plz may u help meh

Excuse me sir/ mamThis que to fin minimum value...Plz may u help meh

Question Image
Grade:11

1 Answers

Sujit Kumar
111 Points
6 years ago
x^2 - y^2=6-2xy
(x^2+y^2)^2=(x^2-y^2)^2 + 4x^2y^2
Substituting \ the \ value \ of \ x^2 - y^2
 
(x^2+y^2)^2=4(9+2x^2y^2-6xy)
Let \ us \ consider \ xy=a
=>(x^2+y^2)^2=4(2a^2-6a+9)
 
We \ know \ the \ minimum \ value \ of \ an \ equation = \frac{-D}{4a}
Where \ D=b^2-4ac
=>min. \ value \ of \ 2a^2-6a+9 \ is \ \frac{9}{2}
Therefore \ (x^2+y^2)^2= 4(9/2)=18
Ans: \ The \ minimum \ value \ of \ (x^2+y^2)^2 \ is \ 18
 

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More