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derive the sin(18) degrees

derive the sin(18) degrees

Grade:12th pass

2 Answers

Vijay Mukati
askIITians Faculty 2590 Points
8 years ago
Let x = 18, so 2x = 36 and 3x = 54. Hence 2x = 90- 3x.
Therefore, sin2x = sin(90-3x) = cos3x
Or 2sinx cosx = 4cos3x – 3cosx.
Hence either cosx = 0 which gives x = 90,
or 2sinx = 4cos2x-3 = 1-4sin2x
Therefore 4sin2x + 2sinx =1.
By Solving the quadratic equation, We have sin (18) = (sqrt(5)-1)/ 4. Thanks.
bheemarasetti
26 Points
6 years ago
Take A=18 so that 5A=90. 5A can be written as. 2A +3A=90 2A=90-3AApply sin on both sides and solve Solve

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