cotpie/20.cot3pie/20.cot5pie/20.cot7pie/20.cot9pie/20
cotpie/20.cot3pie/20.cot5pie/20.cot7pie/20.cot9pie/20
sanjeev , 9 Years ago
Grade 12th pass
Trigonometry> cotpie/20.cot3pie/20.cot5pie/20.cot7pie/2...
1 Answers
Vijay Mukati
Last Activity: 9 Years ago
Dear Student,
cot5pie/20 = cotpi/4 = 1
cotpie/20 = cot(pi/2 β cot9pi/20) = tan9pi/20
cot3pi/20 = cot(pi/2 β 7pi/20) = tan7pi/20
and we know that cotx * tanx = 1.
Therefore. Final answer would be = 1.
Thanks.
cot5pie/20 = cotpi/4 = 1
cotpie/20 = cot(pi/2 β cot9pi/20) = tan9pi/20
cot3pi/20 = cot(pi/2 β 7pi/20) = tan7pi/20
and we know that cotx * tanx = 1.
Therefore. Final answer would be = 1.
Thanks.
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