1800-150-456-789
FlagBACK
Flag Trigonometry> Cot180/18×cot180/9×cot180/4×cot4×180/18×C...
question mark

Cot180/18×cot180/9×cot180/4×cot4×180/18×Cot7×180/18=???????????????????????????????????????????????????????????????????????????????

Shaquib , 6 Years ago
Grade 10
anser 1 Answers
Aditya Gupta

Last Activity: 6 Years ago

Cot180/18×cot180/9×cot180/4×cot4×180/18×Cot7×180/18=Cot10×cot20×cot45×cot40×Cot70
now cot45=1 nd cot20*cot70=cot20*tan70=cot20/cot20=1
so it becomes cot10*cot40.
note that it cannot be simplified further into a closed form

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...

Other Related Questions on trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available

Last Activity: 2 Years ago

question mark
Find the general solution of equation tan3∂=cot2∂For all angles between -720 and +720
trigonometry
0 Answer Available

Last Activity: 2 Years ago

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
0 Answer Available

Last Activity: 2 Years ago

question mark
cos^2 13ºcos^2 47º+cos^2 73º =? …..................
trigonometry
0 Answer Available

Last Activity: 2 Years ago

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
0 Answer Available

Last Activity: 2 Years ago