Question icon
Grade 10Trigonometry

Cot theta +cosec theta -1\cot theta-cosec theta+1=1+cosA\sinA

Profile image of Girish sharma
9 Years agoGrade 10
Answers icon

1 Answer

Profile image of Agrim
9 Years ago
Cot a-1+cosec a/cot a +1-cosec a= (cot a+cosec a)-1/cot a-cosec a+1=cot a +cosec a- (cosec^2a-cot^2a)/cot a - cosec a+1=(cot a+cosec a)-(cot a+cosec a)(cosec a-cot a)/cot a-cosec a+1=(cot a+cosec a)[1-(cosec a-cot a)]/cot a-cosec a+1=(cot a+cosec a)(1+cot a-cosec a)/cot a- cosec a+1=cot a +cosec a=(cos a/sin a)+1/sin a=1+cos a/sin a