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Cot 16. Cot 44+cot 44.cot76 - cot 76.cot16 = Trigonometry problem

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2 years ago

```							Dear student E = cot(76)cot(44) + cot(44)cot(16) - cot(76)cot(16) First, use the formula, cot(A) = tan(90 - A). Then we have : E = tan(14)tan(46) + tan(46)tan(74) - tan(14)tan(74) Rearrange this so the larger numbers are first : E = tan(46)tan(14) + tan(74)tan(46) - tan(74)tan(14) Now we need these two formulae : tan(A + B) = [tan(A) + tan(B)]/[1 - tan(A)tan(B)] which rearranges to : tan(A)tan(B) = 1 - [tan(A) + tan(B)]/tan(A + B) .......... (1) and tan(A - B) = [tan(A) - tan(B)] / [1 + tan(A)tan(B)] which rearranges to : tan(A)tan(B) = [tan(A) - tan(B)]/tan(A - B) - 1 ............ (2) For the 1st expression of E, use (1) : tan(46)tan(14) = 1 - [tan(46) + tan(14)]/tan(60) But tan(60) = √3, so, tan(46)tan(14) = 1 - [tan(46 + tan(14)]/√3 = 1 - tan(46)/√3 - tan(14)/√3 ........... (3) For the 2st expression of E, use (1) : tan(74)tan(46) = 1 - [tan(74) + tan(46)]/tan(120) But tan(120) = -√3, so, tan(74)tan(46) = 1 - [tan(74) + tan(46)]/(-√3) = 1 + tan(74)/√3 + tan(46)/√3 ..... (4) For the 3st expression of E, use (2) : -tan(74)tan(14) = -{[tan(74) - tan(14)]/tan(60) - 1} But tan(60) = √3, so, -tan(74)tan(14) = -{[tan(74) - tan(14)]/√3 - 1} = -tan(74)/√3 + tan(14)/√3 + 1 .... (5) Now add, (3) + (4) + (5), which gives the answer, E = 3.   RegardsArun (askIITians forum expert)
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2 years ago
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