Flag Trigonometry> (cosecA-sinA)(secA-cosA) =1/tanA+cotA...
question mark

(cosecA-sinA)(secA-cosA) =1/tanA+cotA

rachel , 10 Years ago
Grade 10
anser 4 Answers
Nishant Vora

Last Activity: 10 Years ago

Hello Student, Please find the solution

(cosecA-sinA)(secA-cosA)
=(1/sinA – sinA )(1/cosA – cosA)
=[(1- sin2A)/sinA][(1-cos2A)/cosA]
=[(cos2A)/sinA][(sin2A)/cosA]
=sinA*cosA
\frac{sinA cosA}{sin^2A + cos^2A}

= \frac{1}{sin^2A/sinA cosA + cos^2A/sinA cosA }

=\frac{1}{tanA + cotA }
=rhs

I hope it is clear
Thanks

Animesh singh

Last Activity: 7 Years ago

LHS:-(cosecA-sinA) (secA-cosA)(1/sinA-sinA)(1/cosA-cosA)(1-sin²A/sinA) (1-cos²A/cosa)(Cos²A/sinA)(sin²A/cosA)SinA.cosaRHS:-1/tanA+cotA1/(sinA/cosa+cosa/sinA)1/(sin²A+cos²A/sinAcosA)SinA.cosA/1SinA.cosa LHS=RHShence proved.... Answered by:- Animesh singh (MASTERMIND)

Animesh singh

Last Activity: 7 Years ago

LHS:-(cosecA-sinA) (secA-cosA)=(1/sinA-sinA)(1/cosA-cosA)=(1-sin²A/sinA) (1-cos²A/cosa)=(Cos²A/sinA)(sin²A/cosA)=SinA.cosaRHS:-1/tanA+cotA=1/(sinA/cosa+cosa/sinA)=1/(sin²A+cos²A/sinAcosA)=SinA.cosA/1=SinA.cosa LHS=RHShence proved.... Answered by:- Animesh singh (MASTERMIND)

Komal yadav

Last Activity: 6 Years ago

Taking LHS: (1/sinA-sinA/1) (1/cosA-cosA/1) 
=(1-sin2A/sinA) (1-cos2A/cosA)
=(cos2A/sinA) (sin2A/cosA)
=(cos2A.sin2A/sinA.cosA)          
=Taking RHS: 1/sinA/cosA+cosA/sinA
=Taking LCM sin2A+cos2A/sinA.cosA
sinA. cosA
Hence proved

Provide a better Answer & Earn Cool Goodies

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free