Last Activity: 10 Years ago
Hello Student, Please find the solution(cosecA-sinA)(secA-cosA)=(1/sinA – sinA )(1/cosA – cosA)=[(1- sin2A)/sinA][(1-cos2A)/cosA]=[(cos2A)/sinA][(sin2A)/cosA]=sinA*cosA= ==rhsI hope it is clearThanks
Last Activity: 7 Years ago
LHS:-(cosecA-sinA) (secA-cosA)(1/sinA-sinA)(1/cosA-cosA)(1-sin²A/sinA) (1-cos²A/cosa)(Cos²A/sinA)(sin²A/cosA)SinA.cosaRHS:-1/tanA+cotA1/(sinA/cosa+cosa/sinA)1/(sin²A+cos²A/sinAcosA)SinA.cosA/1SinA.cosa LHS=RHShence proved.... Answered by:- Animesh singh (MASTERMIND)
LHS:-(cosecA-sinA) (secA-cosA)=(1/sinA-sinA)(1/cosA-cosA)=(1-sin²A/sinA) (1-cos²A/cosa)=(Cos²A/sinA)(sin²A/cosA)=SinA.cosaRHS:-1/tanA+cotA=1/(sinA/cosa+cosa/sinA)=1/(sin²A+cos²A/sinAcosA)=SinA.cosA/1=SinA.cosa LHS=RHShence proved.... Answered by:- Animesh singh (MASTERMIND)
Last Activity: 6 Years ago
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