Akshat Dubey
Last Activity: 9 Years ago
coseca+cota=p
now, cosec2a – cot2a = 1 …(1)
or, (coseca+cota) (coseca-cota) = 1
or, p(coseca-cota)=1
or, coseca-cota = 1/p ...(2)
add eqn (1) and (2)
coseca + cota + coseca – cota = p+ 1/p
or, 2coseca = (p2+1)/p
or, 2/sina = (p2+1)/p
or, sina = 2p/(p2+1)
now, (1) – (2)
coseca + cota – coseca + cota = p – 1/p
or, 2cota = (p2 - 1)/p
or, 2(cosa/sina) = (p2 - 1)/p
or, 2 [cosa / 2p/(p2+1)] = (p2 - 1)/p
or, 2 cosa * (p2 + 1) / 2p = (p2 - 1)/p
or, cosa = (p2 – 1)/ (p2 + 1)
or, seca = (p2 + 1) / (p2 – 1) …(3)
now, tana = sina/cosa = [2p/+1)2(p] / [(p2 – 1)/ + 1)2(p]
or, tana = 2p /(p2 – 1) ...(4)
now, (3) – (4)
seca – tana = [(p2 + 1) / (p2 – 1)] – [2p /(p2 – 1)]
or, seca – tana = (p2 + 1 – 2p) / (p2 – 1)
I know there can be easier and shorter solutions, but this is the one that struck me first!
I hope that’s a correct solution :)