Grade Select GradeTrigonometry
cosA+cosB+cosC=sinA+sinB+sincfind the value of
cos(A-b)+cos(B-c)+cos(C-A)
cosA+cosB+cosC=sinA+sinB+sinc
find the value of
cos(A-b)+cos(B-c)+cos(C-A)
cos(A-b)+cos(B-c)+cos(C-A)
2 Answers
Saurabh Koranglekar
Dear student
Please assume A,B,C to be pi/4
Solution is 0
Regards
Please assume A,B,C to be pi/4
Solution is 0
Regards
Vikas TU
Dear student
The soluton will not be zero ,
It will be 3
Because Cos(pi/4 – pi/4) + Cos(pi/4 – pi/4) + Cos(pi/4 – pi/4) = 3
Hope this will help
Good Luck
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