Cos3A+Cos3B+Cos3C+Cos3π=0, then the least value of sum of two angles is
Krishnaveni , 5 Years ago
Grade 12th pass
Vectors> Cos3A+Cos3B+Cos3C+Cos3π=0, then the least...
1 Answers
Arun
Last Activity: 5 Years ago
Dear student,
COS3B+COS3C+COS3A – 1 = 0
COS3B+COS3C+COS3A=1
COS3B+COS3C+COS3A-1=0
COS3(B+C)/2.COS3(B-C)/2-SIN^3A/2=0
SOLVING WE GET
COS3C/2.COS3B/2.COS3A/2=0
EITHER3C/2=pi
C= 2 pi/3
Hence A+B = pi/3
Hence least value = pi/3
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