Grade 11Trigonometry
COS2A(1-1/4SIN22A)=COS6A-SIN6A
COS2A(1-1/4SIN22A)=COS6A-SIN6A
1 Answer
Yash Baheti
Use these steps to solve.
Use COS 2A = Cos^2A- SIN ^2A
and on RHS, expand by using a^3-b^3= (a-b)(a^2+ab+b^2)
make wholesuquare on RHS which will become 1 and write that 1 as SIN^2 + COS^2, IN LHS wirte SIN2A as 2SIN A COS A. You will get LHS = RHS.
Use COS 2A = Cos^2A- SIN ^2A
and on RHS, expand by using a^3-b^3= (a-b)(a^2+ab+b^2)
make wholesuquare on RHS which will become 1 and write that 1 as SIN^2 + COS^2, IN LHS wirte SIN2A as 2SIN A COS A. You will get LHS = RHS.
Other Related Questions on trigonometry
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
Last Activity: 3 Years ago
- Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
- Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
Last Activity: 4 Years ago
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
Last Activity: 4 Years ago
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥
trigonometry
Last Activity: 4 Years ago