Cos(x)+2cos(y)+3cos(z)=6 thenTan(t)+ tan(y)+tan(z)=?

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I think that question is wrong because there is no term containing parameter ‘t’ in cos. Rather it would be tan(x)+tan(y)+tan(z)

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Cos(x)+2cos(y)+3cos(z)=6 thenTan(t)+ tan(y)+tan(z)=?

Cos(x)+2cos(y)+3cos(z)=6 thenTan(t)+ tan(y)+tan(z)=?

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Cos(x)+2cos(y)+3cos(z)=6 thenTan(t)+ tan(y)+tan(z)=?

Cos(x)+2cos(y)+3cos(z)=6 thenTan(t)+ tan(y)+tan(z)=?

1 Answers

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Other Related Questions on Trigonometry

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