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cos square 24 degree – cos square 6 degree = A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8

cos square 24 degree – cos square 6 degree =
A)(root5-1)/2       B)(root5+1)/2       C)(root5-1)/8         D)-(root5-1)/8

Question Image
Grade:11

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
one month ago
Dear Student

cos224 = 1 –sin224......(1)
cos26 = 1 –sin26........(2)
subtracting equation 2 from 1
letcos square 24 degree – cos square 6 degree =x
x= – sin224 + sin26

699-1577_b3fbdfbe23841f99d78ba4302b4be1f5.jpg

so answer will be (1/8) ( 1 – √5)

Thanks

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