cos square 24 degree – cos square 6 degree = A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8

Question

Harshit Singh · Answer

Dear Student cos 2 24 = 1 &ndash;sin 2 24......(1) cos 2 6 = 1 &ndash;sin 2 6........(2) subtracting equation 2 from 1 letcos square 24 degree &ndash; cos square 6 degree =x x= &ndash; sin 2 24 + sin 2 6 so answer will be (1/8) ( 1 &ndash; &radic;5) Thanks

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cos square 24 degree – cos square 6 degree = A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8

cos square 24 degree – cos square 6 degree =
A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8

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cos square 24 degree – cos square 6 degree = A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8

cos square 24 degree – cos square 6 degree =A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8

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cos square 24 degree – cos square 6 degree =
A)(root5-1)/2 B)(root5+1)/2 C)(root5-1)/8 D)-(root5-1)/8