cos A+cos2 A=1 , Then sin2A+Sin4A=?

cosA + cos2A = 1 => cos2A = 1 – cosA=> sin2A = 1 – cos2A = 1 – (1 – cosA) = cosANow, sin2A + sin4A = sin2A (1 + sin2A) = cosA ( 1 + cosA) = cosA + cos2A = 1 Ans: 1

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Trigonometry

cos A+cos² A=1 , Then sin²A+Sin⁴A=?

nileena

11 Years agoGrade

1 Answer

Y RAJYALAKSHMI

11 Years ago

cosA + cos²A = 1 => cos²A = 1 – cosA

=> sin²A = 1 – cos²A = 1 – (1 – cosA) = cosA

Now, sin²A + sin⁴A = sin²A (1 + sin²A) = cosA ( 1 + cosA) = cosA + cos²A = 1

Ans: 1

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cos A+cos2 A=1 , Then sin2A+Sin4A=?

nileena

1 Answer

Y RAJYALAKSHMI

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