cos 6 a-sin 6 a=cos2a(1-1/4sin 2 2a)

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Nishant Vora · Answer

(cos 2 a) 3 &ndash; (sin 2 a) 3 = (cos 2 a &ndash; sin 2 a )(cos 4 a + sin 4 a + cos 2 a*sin 2 a) = (cos2a)(1 &ndash; 2 cos 2 a*sin 2 a + cos 2 a*sin 2 a) = (cos2a)(1 &ndash; cos 2 a*sin 2 a ) = (cos2a)(1 &ndash; 4cos 2 a*sin 2 a/4 ) = cos2a(1-1/4sin 2 2a)

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cos 6 a-sin 6 a=cos2a(1-1/4sin 2 2a)

cos⁶a-sin⁶a=cos2a(1-1/4sin²2a)

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cos 6 a-sin 6 a=cos2a(1-1/4sin 2 2a)

cos6a-sin6a=cos2a(1-1/4sin22a)

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cos⁶a-sin⁶a=cos2a(1-1/4sin²2a)