Last Activity: 6 Years ago
you can solve
cos4x as
cos2(2x) =1-2sin2(2x)
=1-2(2sinx . cosx)2 { sin2x = 2sinx. cosx}
=1-2(4sin2x.cos2x)
=1-8sin2x.cos2x
LHS=RHS
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Year ago(s)