Rinkoo Gupta12 Years agocos276+cos214-cos76cos16(1+cos152)/2+(1+cos28)/2-cos76cos16=1+1/2[cos(180-28)+cos28]-cos76cos16=1+1/2[-cos28+cos28]-cos76cos16=1-cos76cos16=1-1/2[2cos76cos16]=1-1/2[cos92+cos60]=1-1/2[cos(90+20+1/2]=1-1/2[-sin2+1/2]=1-1/4+1/2 sin2=3/4+(1/2) sin2Thanks & RegardsRinkoo GuptaAskIITians Faculty