0

Guest

Courses New

cos^2(47)+cos^2(73)+cos(47)*cos(73)

cos^2(47)+cos^2(73)+cos(47)*cos(73)

Grade:11

1 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
8 years ago
1/2[2cos^(47)+2cos^(73)+2cos(47)cos(73)]
=1/2[1+cos(94)+1+cos(146)+cos(120)+cos(26)]
=1/2[2+cos(94)+cos(146)-(1/2)+cos(26)]
=1/2[3/2+{cos(94)+cos(26)}+cos(146)]
=1/2[3/2+2cos(120)cos(34)+cos(146)]
=1/2[3/2+2(1/2)cos(34)+cos(146)]
=1/2[3/2+cos(34)+cos(146)]
=1/2[3/2+2cos(90)cos(56)]
=1/2[3/2+2(0).cos(56)]
=1/2[3/2+0]
=3/4 Ans.
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More