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cos^2(47)+cos^2(73)+cos(47)*cos(73)
1/2[2cos^(47)+2cos^(73)+2cos(47)cos(73)]=1/2[1+cos(94)+1+cos(146)+cos(120)+cos(26)]=1/2[2+cos(94)+cos(146)-(1/2)+cos(26)]=1/2[3/2+{cos(94)+cos(26)}+cos(146)]=1/2[3/2+2cos(120)cos(34)+cos(146)]=1/2[3/2+2(1/2)cos(34)+cos(146)]=1/2[3/2+cos(34)+cos(146)]=1/2[3/2+2cos(90)cos(56)]=1/2[3/2+2(0).cos(56)]=1/2[3/2+0]=3/4 Ans.Thanks & RegardsRinkoo GuptaAskIITians Faculty
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