Cos π/15 *cos2π/15*cos3π/15*cos4π/15cos 5π/15*cos6π/15 *cos7π/15= 1/128

Question

Arun · Answer

= (1/16) * (1/4) * (1 / 2) = 1/128 Therefore, the left sin (4π / 5) = sin (π / 5) Note that sin (16π / 15) = - sin (π / 15) (4π / 5) / [4sin (π / 5)]} * (1/2) (using the conclusion (1) (1) 2)) = - [cos (π / 15 ) cos (2π / 15) cos (4π / 15) cos (8π / 15)] * [cos (π / 5) cos (2π / 5)] * (1/2) then left the formula cos (5π / 15) = cos ( π / 3) = 1/2 cos (6π / 15) = cos (2π / 5) cos (3π / 15) cos (π / 5) cos (7π / 15) = cos (8π / 15) cos (2π / 15) cos (4π / 15) cos (7π / 15) * [cos (3π / 15) cos (5π / 15) cos (6π / 15) = cos (π / 15) cos (2π / 15) cos (3π / 15) cos (4π / 15) cos (5π / 15) cos (6π Cos (7π / 15) then left the formula = sin16x / [16sinx] = 2sin8xcos8x / [16sinx] = 4sin4xcos4xcos8x / [16sinx ] = 8sin2xcos2xcos4xcos8x / [16sinx] = 16sinxcosxcos2xcos4xcos8x / [16sinx] (2) cosxcos2xcos4xcos8x = sin4x / [4sinx] = 2sin2xcos2x / [4sinx] = 4sinxcosxcos2x / [4sinx] (1) cosxcos2x The following two conclusions are noted:

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Cos π/15 cos2π/15cos3π/15cos4π/15cos 5π/15cos6π/15 *cos7π/15= 1/128

Cos π/15 cos2π/15cos3π/15cos4π/15cos 5π/15cos6π/15 *cos7π/15= 1/128

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Trigonometry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship