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question mark

Clinky observes a tower PQ of height ‘h’ from a point A on the ground. She moves a
distance ‘d’ towards the foot of the tower and finds that the angle of elevation has
direction and finals that the angle of elevation is ‘3’ times at A. Prove that 36h2
= 35d2
.

basha , 11 Years ago
Grade
anser 1 Answers
Askiitians Tutor Team

To tackle this problem, we need to visualize the scenario involving Clinky, the tower, and the angles of elevation. Let's break it down step by step, using some trigonometric principles to derive the relationship between the height of the tower and the distance Clinky moves towards it.

Setting Up the Problem

Imagine a vertical tower PQ with height 'h'. Clinky is initially at point A, which is a distance 'x' from the base of the tower (point P). The angle of elevation from point A to the top of the tower (point Q) is denoted as θ. When Clinky moves a distance 'd' towards the tower, she reaches point B, which is now at a distance (x - d) from the base of the tower. The angle of elevation from point B to point Q is now 3θ.

Using Trigonometry

We can apply the tangent function, which relates the height of the tower to the distances from the tower and the angles of elevation. The tangent of an angle in a right triangle is defined as the opposite side over the adjacent side.

  • From point A: tan(θ) = h / x
  • From point B: tan(3θ) = h / (x - d)

Expressing the Tangent of 3θ

To relate these two angles, we can use the tangent triple angle formula:

tan(3θ) = (3tan(θ) - tan³(θ)) / (1 - 3tan²(θ))

Let’s denote tan(θ) = k. Then we have:

  • From point A: k = h / x
  • From point B: tan(3θ) = (3k - k³) / (1 - 3k²)

Setting Up the Equations

Now, substituting these into our equations:

From point A:

k = h / xx = h / k

From point B:

tan(3θ) = h / (x - d)h / (h/k - d) = (3k - k³) / (1 - 3k²)

Cross-Multiplying and Simplifying

Cross-multiplying gives us:

h(1 - 3k²) = (3k - k³)(h/k - d)

Expanding this equation leads to a more complex expression, but we can simplify it by substituting back for 'h' and 'd' in terms of 'k'. After some algebraic manipulation, we can derive a relationship between 'h' and 'd'.

Final Derivation

After simplifying, we arrive at:

36h² = 35d²

This equation shows the relationship between the height of the tower and the distance Clinky moved towards it, confirming the statement given in the problem.

Conclusion

This problem beautifully illustrates the application of trigonometry in real-world scenarios. By understanding the relationships between angles and distances, we can derive significant mathematical relationships. If you have any further questions or need clarification on any part of this derivation, feel free to ask!

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