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Answer plz
Facing problem in this question .........?.............................................................................................

Anshul Das , 6 Years ago
Grade 11
anser 1 Answers
Sargam
=(tan2x-tan x)(tan 2x+tan x)/(1+tan^2 2x tan^2 x)(1-tan^2 2x tan^2 x)
Using the identity a^2 -b^2= (a+ b)( a – b) in both numerator and denominator 
=(tan2x-tan x)/(1+tan^2 2x tan^2 x) *(tan 2x+tan x)/(1-tan^2 2x tan^2 x)
Using tan ( A + B ) indentity in the first part and tan(A-B ) in second 
You get the answer 
Last Activity: 6 Years ago
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