A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is?

ans:d = 2πrθ/360
=> 44 = 56πr/360
=>r = (36044)/56π
=>r = (360447)/5622
=>r = 90m

in this solution derive for:
d = 2πrθ/360

Question

A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is?

ans:d = 2πrθ/360
=> 44 = 56πr/360
=>r = (360*44)/56π
=>r = (360*44*7)/56*22
=>r = 90m

in this solution derive for:

d = 2πrθ/360

Deepak Kumar Shringi · Answer

we aleady know that d=r&theta; here&theta; is in radian and 360=2&pi; radian 1 =2&pi;/360 just convert this radian in degree now

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A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is? ans: d = 2πrθ/360 => 44 = 56πr/360 =>r = (36044)/56π =>r = (360447)/5622 =>r = 90m in this solution derive for: d = 2πrθ/360

A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is?

ans:d = 2πrθ/360
=> 44 = 56πr/360
=>r = (36044)/56π
=>r = (360447)/5622
=>r = 90m

in this solution derive for:
d = 2πrθ/360

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A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is? ans: d = 2πrθ/360 => 44 = 56πr/360 =>r = (360*44)/56π =>r = (360*44*7)/56*22 =>r = 90m in this solution derive for: d = 2πrθ/360

A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is? ans:d = 2πrθ/360 => 44 = 56πr/360 =>r = (360*44)/56π =>r = (360*44*7)/56*22 =>r = 90m in this solution derive for:d = 2πrθ/360

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A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is? ans: d = 2πrθ/360 => 44 = 56πr/360 =>r = (36044)/56π =>r = (360447)/5622 =>r = 90m in this solution derive for: d = 2πrθ/360

A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is?

ans:d = 2πrθ/360
=> 44 = 56πr/360
=>r = (36044)/56π
=>r = (360447)/5622
=>r = 90m

in this solution derive for:
d = 2πrθ/360