A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is? ans:d = 2πrθ/360
=> 44 = 56πr/360
=>r = (360*44)/56π
=>r = (360*44*7)/56*22
=>r = 90m in this solution derive for:d = 2πrθ/360
A rail road curve is to be laid out on a circle. If the track is to change its direction by 28 degrees in a dist. of 44 m then the radius of the curve is?
ans:d = 2πrθ/360
=> 44 = 56πr/360
=>r = (360*44)/56π
=>r = (360*44*7)/56*22
=>r = 90m
=> 44 = 56πr/360
=>r = (360*44)/56π
=>r = (360*44*7)/56*22
=>r = 90m
in this solution derive for:
d = 2πrθ/360
Purva Agrawal , 6 Years ago
Grade 11
