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        A quadratic equation whose roots are cosec square thita and sec square thita can be
one year ago

							Dear student Equation can be as follows- x² - ( cosec²theta + sec² theta) + cosec ²theta * sec²theta = 0 x² - (tan theta + cot theta)² x + 1/sin²theta * cos²theta = 0 RegardsArun (askIITians forum expert)

one year ago
							As you know if  , are the roots of a quadratic equation then the equation formed is :   x2 -(  +)x + .=0 => x2 -( cosec2  + sec2)x +cosec2  . sec2=0 => x2 -( 1/sin2 + 1/cos2 )x + 1/sin2 .1/cos2 =0=>x2 -( sin2 + cos2 ). (1/sin2 .cos2 )x + 1/sin2 .1/cos2 =0 x2 -( 1/(sin2 .cos2 )x + 1/sin2 .1/cos2 =0=> (sin2 .cos2 ) x2  -x  +1=0kkbisht

one year ago
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