help@askiitians.com

1800-150-456-789

Trigonometry> a quadratic equation whose roots are cose...

question mark

a quadratic equation whose roots are cosec²theta and sec² theta can be

x^2-2x+2=0

x^2-3x+3=0

x^2-5x+5=0

none

ShivaDhanush , 8 Years ago

Grade 12

1 Answers

Ketan Prakash

Last Activity: 6 Years ago

Sec²a+cosec²a=1/sin²a+1/cos²a

=sin²a+cos²a/sin²acos²a=4/sin²2a

Sin2a=2sina cos a

Sina cosa = 1/2 sin2a

Sum of the roots = 4/sin²2a > or = 4

Products of roots = 4/sin²2a > or equals to 4

Both sum of roots and prouct of roots are equal.let it t.

Hence , equation will be x²- tx + t=0 (t always greater or equals to 4)

Hence , x²-5x+5=0 is one of the solution.

LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

Full Live Access

Study Material

Live Doubts Solving

Daily Class Assignments

In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.

trigonometry

1 Answer Available

Last Activity: 2 Years ago

Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720

trigonometry

0 Answer Available

Last Activity: 3 Years ago

To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA

trigonometry

0 Answer Available

Last Activity: 3 Years ago

cos^2 13ºcos^2 47º+cos^2 73º =? …..................

trigonometry

0 Answer Available

Last Activity: 3 Years ago

Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)

trigonometry

0 Answer Available

Last Activity: 3 Years ago

View all Questions