0

Guest

Courses New

a quadratic equation whose roots are cosec 2 theta and sec 2 theta can be x^2-2x+2=0 x^2-3x+3=0 x^2-5x+5=0 none

a quadratic equation whose roots are cosec2 theta and sec2 theta can be 
  • x^2-2x+2=0
  • x^2-3x+3=0
  • x^2-5x+5=0
  • none

Grade:12

1 Answers

Ketan Prakash
31 Points
4 years ago
Sec2a+cosec2a=1/sin2a+1/cos2a
=sin2a+cos2a/sin2acos2a=4/sin22a
 
Sin2a=2sina cos a
Sina cosa = 1/2 sin2a
 
Sum of the roots = 4/sin22a  > or = 4
 
Products of roots = 4/sin22a > or equals to 4
 
Both sum of roots and prouct of roots are equal.let it t.
 
Hence , equation will be x2 - tx + t=0  (t always greater or equals to 4)
 
Hence , x2-5x+5=0 is one of the solution.

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More