A + B + C = π (cotA+cotB+cotC)÷(cotA×cotB×cotC) = (a) 1(b) cotAcotBcotC(c) -1(d) 0 My attempt at solution: Let A = B = C = π÷3 Then,cot(A) + cot(B) + cot(C) = 3 × cot(π÷6) = 3 × (1÷√3) = √3 And,cotA × cotB × cotC = (1÷√3)^(3) =1÷(3√3) Therefore, answer should be 9.What am I doing wrong?Source: BITSAT Paper 2012.
A + B + C = π
(cotA+cotB+cotC)÷(cotA×cotB×cotC) =
(a) 1
(b) cotAcotBcotC
(c) -1
(d) 0
My attempt at solution:
Let A = B = C = π÷3
Then,
cot(A) + cot(B) + cot(C) = 3 × cot(π÷6) = 3 × (1÷√3) = √3
And,
cotA × cotB × cotC = (1÷√3)^(3) =1÷(3√3)
Therefore, answer should be 9.
What am I doing wrong?
Source: BITSAT Paper 2012.
Dhruvit Raithatha , 8 Years ago
Grade 12th pass
