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Trigonometry

A+B=π/2 and B+C=A, then tan A=?
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Profile image of Shubh Bhinde
7 Years agoGrade
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1 Answer

Profile image of Rohit verma
ApprovedApproved Tutor Answer7 Years ago
  1. TanA=tan pi-B
  2.  TanA= cotB
  3.  C=A-B
  4. TanC = Tan (A-B)
  5. Tanc=tanA-tanB/1+tanAtanB
  6. TanA=cotB
  7.  Hence tanC = tan A - tanB/1+1
  8. 2TanC=tanA-TanB
  9. Hence tTanA=2TanC+tanB
  10. 2tanC=tanA -tan