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7sin 2 x + 3cos 2 x = 4, solve for x.
Hello student, 7sin2x + 3cos2x = 4So, 4sin2x + 3sin2x + 3cos2x = 44sin2x + 3 (sin2x + cos2x) = 44sin2x + 3(1) = 44sin2x = 4 – 34sin2x = 1sin2x = ¼sin x = ½So, x = 30 degree.
Dear student,Please find the solution to your problem below. 7sin2x + 3cos2x = 4So, 4sin2x + 3sin2x + 3cos2x = 44sin2x + 3 (sin2x + cos2x) = 44sin2x + 3(1) = 44sin2x = 4 – 34sin2x = 1sin2x = ¼Hence, sinx = ½ or – ½Hence, x = 30o, 150o or 210o, 330oThe general solution can be written as, x = nπ ± π/6 Hope it helps.Thanks and regards,Kushagra
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