7sin 2 x + 3cos 2 x = 4, solve for x.

Question

Latika Leekha · Answer

Hello student, 7sin 2 x + 3cos 2 x = 4 So, 4sin 2 x + 3sin 2 x + 3cos 2 x = 4 4sin 2 x + 3 (sin 2 x + cos 2 x) = 4 4sin 2 x + 3(1) = 4 4sin 2 x = 4 &ndash; 3 4sin 2 x = 1 sin 2 x = &frac14; sin x = &frac12; So, x = 30 degree.

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem below. 7sin 2 x + 3cos 2 x = 4 So, 4sin 2 x + 3sin 2 x + 3cos 2 x = 4 4sin 2 x + 3 (sin 2 x + cos 2 x) = 4 4sin 2 x + 3(1) = 4 4sin 2 x = 4 – 3 4sin 2 x = 1 sin 2 x = ¼ Hence, sinx = ½ or – ½ Hence, x = 30 o , 150 o or 210 o , 330 o The general solution can be written as, x = n π ± π/6 Hope it helps. Thanks and regards, Kushagra

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7sin 2 x + 3cos 2 x = 4, solve for x.

7sin²x + 3cos²x = 4, solve for x.

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7sin 2 x + 3cos 2 x = 4, solve for x.

7sin2x + 3cos2x = 4, solve for x.

2 Answers

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7sin²x + 3cos²x = 4, solve for x.