Kartik
Last Activity: 7 Years ago
we have,
3sina=5sinb
rearranging it
(sina/sinb)=(5/3)
now applying componendo and dividendo rule
we get
(sina+sinb)/(sina-sinb)=4
now using the identities of trigonometry we get
(2sin((a+b)/2)cos((a-b)/2) )/( 2cos((a+b)/2)sin((a-b)/2))=4
this becomes
(tan((a+b)/2) )/( tan((a-b)/2)=4