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37,39

37,39

Question Image
Grade:11

1 Answers

Aakanksha Talreja
34 Points
5 years ago
Image not clear so solution according to what I understand n due to it can’t understand 37th
39) x=3\cos \theta & y=3sin\theta
a=2\cos \phi b=4/3\sin \phi
\therefore 4a^{2}x^{2}+9b^{2}y^{2}-12abxy=4(4cos^{2}\phi *9\cos ^{2 }\theta )+9(16/9\sin ^{2}\phi *9\sin ^{2}\theta )-12(8/3\cos \phi \sin \phi *9\cos \theta \sin \theta )
=144[\cos ^{2}(\theta +\phi )+(\sin 2\phi *\sin 2\theta)/2 ]-72\sin 2\phi *\sin 2\theta
=144\cos ^{2}(\theta +\phi) +72\sin 2\theta *\sin 2\phi -72\sin 2\theta *\sin 2\phi =144\cos ^{2}(\theta +\phi )=144
 

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