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2tan^2A tan^2B tan^C+tan^2B tan^2C+ tan^2C tan^2A+ tan^2C tan^A=1 Prove that sin^2A +sin^2B +sin^2C=1

2tan^2A tan^2B tan^C+tan^2B tan^2C+ tan^2C tan^2A+ tan^2C tan^A=1
Prove that sin^2A +sin^2B +sin^2C=1

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
2 years ago
Dear student

There must be more information in the question, kindly check and repost

Regards

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