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if a cos 2Φ + b sin 2Φ =c has p & q as its solutions, then prove that
tan p + tan q =2b/a+c & tan p * tan q = c-a/a+c.
Dear nishant
a cos 2Φ + b sin 2Φ =c
a(1-tan2Φ)/(1+tan2Φ) + b (2tanΦ)/(1+tan2Φ) =c
tan2Φ(a+c) +tanΦ(-2b) +(c-a)=0
now tan p and tanq are the solution of this equation
tanp + tanq = 2b/(a+c)
tanp*tanq = (c-a)/(c+a)
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