in a ΔABC, if cos A/a=cos B/b=cos C/c and the side a=2, then area of the Δ is....?

Dear nishant

cos A/a=cos B/b=cos C/c  =m

cosA =am  ,cosB =bm  =cosC=c m

we know that

 sinA/a =sinB/b =sinC/c  =n

so SinA =an  , sinB =bn  ,sinC = cn

devide   tanA =tanB =tanC =n/m

  so A=B =C

triangle is equileteral

area =√3 /4 *2²

         =√3 unit

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