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`        A circle inscribed in a triangle has radius 4. Circle touches BC at D \$ BD is 6 \$ DC is 8 .  Find the area of triangle`
8 years ago

147 Points
```										Dear Mayank

tanB/2 = 2/3
so sinB = 2tanB/2  / (1+ tan2B/2)  = 12/13
cosB  = (1-tan2B/2)/(1+ tan2B/2) =5/13

tanC/2 = 1/2
so sinC = 2tanC/2  / (1+ tan2C/2)  = 4/5
cosC  = (1-tan2C/2)/(1+ tan2C/2)  =3/5

so sinA =sin(180- B-C) =sin(B+C) = sinBcosC +cosBsinC
=56/65
so area of triangle = a2 sinB sinC /2sinA       where a = 8+6 =14
=84
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
```
8 years ago
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