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in a triangle angle A > angle B. if the measured angles A and B satisfy the equation 3sinx - 4sin 3 x + k = 0, 0

in a triangle angle A > angle B. if the measured angles A and B satisfy the equation 3sinx - 4sin3x + k = 0, 0

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear

3sinx - 4sin3x + k = 0

sin3x =-k

since  0<k<1

 so    -1<sin3x<0 ...............1

        A and B are angel of triangle so 

  0< A,B,A+B<∏

 0<3A,3B<3∏

 from equation 1 

∏ <3A,3B <2∏

A and B angel satisfied the equation 1  then

A+B =∏

so angel C=0 which is not possible in a triangle.

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