Rajesh Dang , 12 Years ago
Grade Upto college level
Trigonometry> compound angles...
2 AnswersVineeth
i got the answer 1 month ago but how should i post that in the form of a photo(.jpg)
Vineeth
{2[2sin(P/7)Cos(P/7)]Cos(2P/7)}/Sin(P/7)-1
=[2sin(2P/7)Cos(2P/7)]/Sin(P/7)-1
=Sin(4P/7) -1
Sin(P/7)
=Sin(P-4P/7) -1
Sin(P/7)
=Sin(3P/7) -1
Sin(p/7)
=Sin(3P/7)-Sin(P/7)
Sin(P/7)
=2Cos[(3P+P)/2*7]Sin[(3P-P)/2*7]
Sin(P/7)
=2Cos(2P/7)Sin(P/7)
Sin(P/7)
=2Cos(2P/7)
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