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Grade:Upto college level

2 Answers

Vineeth
35 Points
7 years ago
i got the answer 1 month ago but how should i post that in the form of a photo(.jpg)
Vineeth
35 Points
7 years ago
{2[2sin(P/7)Cos(P/7)]Cos(2P/7)}/Sin(P/7)-1 =[2sin(2P/7)Cos(2P/7)]/Sin(P/7)-1 =Sin(4P/7) -1 Sin(P/7) =Sin(P-4P/7) -1 Sin(P/7) =Sin(3P/7) -1 Sin(p/7) =Sin(3P/7)-Sin(P/7) Sin(P/7) =2Cos[(3P+P)/2*7]Sin[(3P-P)/2*7] Sin(P/7) =2Cos(2P/7)Sin(P/7) Sin(P/7) =2Cos(2P/7)

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