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sin -1 x + sin -1 2x = ∏/3

sin-1x + sin-12x = ∏/3

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear Aby

  -1≤ 2x≤1

  -1/2 ≤x≤1/2

now

sin-1x + sin-12x = ∏/3

 sin-12x = ∏/3  -sin-1x

take sin

   2x = sin∏/3 cos sin-1x  -cos∏/3  sinsin-1x

        =√3 /2 √(1-x2)  -1/2 x

 or  5x/2  =√3 /2 √(1-x2)

square

  25x2 =3 (1-x2)

  x2 =3/28

 x= =±√3/28

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Badiuddin

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