if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0

then 2cos(a+b) = ?

answer is xy + 1/xy .how is it??

my answer is coming x/y + y/x

Question

if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0 t hen 2cos(a+b) = ? answer is xy + 1/xy .how is it?? my answer is coming x/y + y/x

Amit Jain · Answer

Thanks & Regards Amit Jain, askIITians Faculty B.Tech., IIT Delhi

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if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0 t hen 2cos(a+b) = ? answer is xy + 1/xy .how is it?? my answer is coming x/y + y/x

if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0

then 2cos(a+b) = ?

answer is xy + 1/xy .how is it??

my answer is coming x/y + y/x

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if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0 t hen 2cos(a+b) = ? answer is xy + 1/xy .how is it?? my answer is coming x/y + y/x

if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0 then 2cos(a+b) = ? answer is xy + 1/xy .how is it?? my answer is coming x/y + y/x

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if x^(2) -2xcos(a) +1=0 and y^(2) -2ycos(b)+1=0

then 2cos(a+b) = ?

answer is xy + 1/xy .how is it??

my answer is coming x/y + y/x