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more than one options may be correct Q. for an +ve integer n, let fn(x)= {tan(x/2)}(1+secx)(1+sec2x)(1+sec4x).............(1+sec2 n x). Then (a)f 2 (pie/16) (b)f3(pie/32) (c)f4(pie/64) (d)f5(pie/128)

more than one options may be correct


Q. for an +ve integer n, let fn(x)= {tan(x/2)}(1+secx)(1+sec2x)(1+sec4x).............(1+sec2nx). Then


(a)f2(pie/16)


(b)f3(pie/32)


(c)f4(pie/64)


(d)f5(pie/128)


 


 


 


 


 


 


 

Grade:12

2 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear raman

fn(x)= {tan(x/2)}(1+secx)(1+sec2x)(1+sec4x).............(1+sec2nx).

simplyfy first bracket 

       =tanx/2 (2cos2(x/2) /cosx))(1+sec2x)(1+sec4x).............(1+sec2nx).

        =tanx (1+sec2x)(1+sec4x).............(1+sec2nx).

 similery solve other bracket also 

  fn(x) =tan2nx  

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Badiuddin

Priyansh Goel
21 Points
11 years ago

Ans is ABCD.

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