(a) Solve for 0 < θ < 5, the equation 5+3cosec (20θ+1) = 0(b) FInd all the angles between -1800 and 1800 such thatcosec y + 11cot y = 4sin yThanks,Vishnu

Dear Vishnu

a )

5+3cosec (20θ+1) = 0

sin(20θ+1)=-3/5

0 < θ < 5

so  1 < 20 θ +1< 101

for this angel range sin (20θ+1) will always be positive so no solution

b)

cosec y + 11cot y = 4sin y

simplify    4cos²y +11cosy -3=0

 this give cos y=-7/4 and 3/2   which is not posible so no solution exits

---

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin