1800-150-456-789
FlagBACK
Flag Trigonometry> sin^6 x+cos^6x +3sin^2x cos^2x =1...
question mark

sin^6 x+cos^6x +3sin^2x cos^2x =1

pradeep , 11 Years ago
Grade 6
anser 1 Answers
Rinkoo Gupta

Last Activity: 11 Years ago

Dear student,

If your ques is that To prove the identity sin^6x+cos^6x+3sin^2xcos^2x=1
then your solution is :
L.H.S.= sin^6x+cos^6x+3 sin^2xcos^2x
using formula a^3+b^3=(a+b)(a^2+b^2-ab), we get
(sin^2x+cos^2x){ sin^4x+cos^4x-sin^2xcos^2x} + 3 sin^2xcos^2x
=sin^4xcos^4x+2sin^2xcos^2x
=(sin^2x+cos^2x)^2
=1

Thanks & Regards
Rinkoo Gupta
AskIITians Faculty

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Other Related Questions on trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available

Last Activity: 2 Years ago

question mark
  • Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
0 Answer Available

Last Activity: 3 Years ago

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
0 Answer Available

Last Activity: 3 Years ago

question mark
cos^2 13ºcos^2 47º+cos^2 73º =? …..................
trigonometry
0 Answer Available

Last Activity: 3 Years ago

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
0 Answer Available

Last Activity: 3 Years ago