Trigonometry> trigonometic-equations...

The set of values of x for which tan3x-tan2x/1+tan3xtan2x=1 is

Pavan Boro , 12 Years ago

Grade 12

10 Answers

Radhika Batra

WE KNOW

tanx = tan(3x-2x) = (tan3x - tan2x)/(1+tan3xtan2x)

therefore the above problem reduce to

tanx=1

then find x.

Last Activity: 12 Years ago

Kevin Nash

(tan 3x - tan 2x) / (1 + tan 3x tan 2x) = tan (3x-2x) = tan x

So the equation becomes tan x = 1 = tan (pi/4)

Whose general solution is x = n*pi + pi/4 = (n+1/4) * pi

Last Activity: 12 Years ago

Kaushik

tan(3x-2x)=1

tanx=1

x=n*pi + (pi/4)

Last Activity: 12 Years ago

jitender lakhanpal

hi pavan

the Kaushik is correct

you just have to apply tan ( A - B ) formula

tan (A-B) = (tanA - tan B )/(1 - tanA tan B )

take A = 3 x and B = 2x

jitender

askiitians expert

Last Activity: 12 Years ago

Amit Nardiya

We know that tan (A - B) = (tan A- tan B) / (1+ tan A. tanB) So (tan3x - tan2x) / (1+ tan3x tan2x) = tan (3x - 2x) = tan x So we have to find solution of tan x = 1 So x = p / 4 will 1 solution and x = np + p/4 will be general solution of equation. Thanks & Regards, Amit Nardiya, askIITians faculty.

Last Activity: 12 Years ago

rakib ansari

Last Activity: 11 Years ago

Harsh Srivastava

The answer for the given question is phi (?) or a null set.. tan (A - B) = (tan A- tan B) / (1+ tan A. tanB) So (tan3x - tan2x) / (1+ tan3x tan2x) = tan (3x - 2x) = tan x So we have to find solution of tan x = 1 So x = p / 4 will 1 solution and x = np + p/4 will be general solution of equation. But if x= p / 4 then, 2x= p / 2. And tan2x will not be defined.. You can check for other values of x as well...So The answer is phi (?) or a null set.

Last Activity: 11 Years ago

Shreyas V S

The answer to this question is there is no set of solutions for this question, because if we take x=π/4 then if we substitute it in the equation we get an indefinite form of (infinity/infinity).... Hence there is no solution to this answer

Last Activity: 8 Years ago

Suhas

Actually the answer is nullset.or pi.

Tan3x-tan2x/1+tan3x2x

=tan(3x-2x)= tanx =1

x=pi/4i

Then if u substitute the value pi/4 , then

(Tan3(pi/4)-tan2(pi/4))/ 1-tan3(pi/4)tan2(pi/4)

Then the terms containing tan2(pi/4) becomes

Tan2(pi/2) in the numerator and in the denominator so the numerator and the denominator becomes infinity as tan(pi/2) is infiniy or not defined so the values of x is null set or phi.

tan3(pi/4)-ta2(

Last Activity: 7 Years ago