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in a triangle abc , cos A+cos B=4 [ sin(C/2)]^2....

then sides a,b,c are in ap/gp/hp/none

rahul agrwl , 12 Years ago
Grade 12
anser 1 Answers
jitender lakhanpal

hi rahul

 

answer -- A.P 

for explanation PFA

1336_36248_solutions of triangles.JPG

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