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from the top of minar ofeight 60m,the top and bottom of a clock tower are observed at an angles of depression of 30 degrees and 60 degrees respectively.then the height of clock tower in meters
40 m....
40metres
Here is yr. soln.
PLZ APPROVE!
tan 30 = AC/BC = 60-h/BC
tan 60 = 60/DE = 60/BC
60-h/tan30 = 60/tan60
√3 (60-h) = 60/√3
3 (60-h) = 60
60-h = 20
h= 40m. Ans.
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