Grade 12Trigonometrynumber of solutions in 0 to pi for sin3x=4sinxsin2xsin4x Rakshith Gore 13 Years agoGrade 12
Saurabh GuptaApproved Tutor Answer13 Years ago sin 3x = 4 sinx sin2x sin4x => sin 3x = 2 sinx (2 sin 2x sin 4x) => sin 3x = 2 sinx {cos (2x-4x) - cos (2x+4x)} => sin 3x = 2 sinx (cos 2x - cos 6x) => sin 3x = 2 sinx cos 2x - 2 sin x cos 6x => sin 3x = {sin (x+2x) + sin (x-2x)} - {sin (x+6x) + sin (x-6x)} => sin 3x = sin 3x + sin (-x) - sin 7x - sin (-5x) => sin x + sin 7x + sin 5x = 0 Now, you can easily plot the curve above and see the number of points of intersection. Curve is shown to you. (Approximate) See the solutions between 0 to π.