Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y=log2(12x-96). What is the value of m+n?

Question

Akash Kumar Dutta · Answer

Dear Vivek,

we have x''=x+m =>m=x''-x
and y'' =y+n =>n=y''-y
hence m+n=(x''+y'') - (x+y)
taking y''=y=1 we get m+n= x''-x
putting y=1 in y=log2 3x.... we get x=2/3
putting y''=1 in y''=log2 (12x''-96)... we get x''=49/6
Hence m+n= x''-x=49/6 - 2/3
=45/6=15/2
hence m+n= 15/2 (ANS).

Regards.

shiddhant bhattacharya · Answer

the answer is 26

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Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y=log2(12x-96). What is the value of m+n?

Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y=log2(12x-96). What is the value of m+n?

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Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y=log2(12x-96). What is the value of m+n?

Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y=log2(12x-96). What is the value of m+n?

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