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sin(2x+x)=sin2x.cosx+cos2x.sinx =2sinxcosx.cosx+(-2sin^2x)sinx =2sinxcos^2+sinx-2sin^3x =sinx(2cos^2x+1)-2sin^3x =sinx(2-2sin^2x+1)-2sin^3x =2sinx-2sin^3x+sinx-2sin^3x = 3sinx-4sin^3x
sin(2x+x)=sin2x.cosx+cos2x.sinx
=2sinxcosx.cosx+(-2sin^2x)sinx
=2sinxcos^2+sinx-2sin^3x
=sinx(2cos^2x+1)-2sin^3x
=sinx(2-2sin^2x+1)-2sin^3x
=2sinx-2sin^3x+sinx-2sin^3x
= 3sinx-4sin^3x
thank you,you missed putting 1 in the second step in your answer
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