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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
y=Θ[sin(lnΘ)+cos(lnΘ)]
dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)
dy/dΘ=2cosΘ
If u like answer please click YES below
WE KNOW
SIN(INθ)+COS(INθ)=PIE/2
y=θ*pie/2
dy÷dθ=pie/2
so
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