Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
RAMESH BHARATHAPU , 13 Years ago
Grade 10
Trigonometry> LOGARITHMS...
2 Answers
Yogita Bang
y=Θ[sin(lnΘ)+cos(lnΘ)]
dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)
dy/dΘ=2cosΘ
If u like answer please click YES below 
Rohan Das
WE KNOW
|
SIN(INθ)+COS(INθ)=PIE/2 |
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y=θ*pie/2
so |
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