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Grade 11Trigonometry

If sinθ+sin2θ=1

Then prove that cos^12θ+3cos^10θ+3cos^8θ+cos^6θ=1

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16 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To tackle the equation \( \sin \theta + \sin 2\theta = 1 \) and prove that \( \cos^{12} \theta + 3\cos^{10} \theta + 3\cos^{8} \theta + \cos^{6} \theta = 1 \), we can start by manipulating the given sine equation. Let's break it down step by step.

Step 1: Simplifying the Sine Equation

We know that \( \sin 2\theta = 2\sin \theta \cos \theta \). Substituting this into the original equation gives us:

\( \sin \theta + 2\sin \theta \cos \theta = 1 \)

Factoring out \( \sin \theta \) yields:

\( \sin \theta (1 + 2\cos \theta) = 1 \)

Step 2: Analyzing the Sine Function

Since \( \sin \theta \) must be between 0 and 1, we can deduce that \( \sin \theta \) must equal 1 for the equation to hold true. This leads us to:

\( \sin \theta = 1 \implies \theta = \frac{\pi}{2} + 2n\pi \) (where \( n \) is any integer)

At this angle, \( \cos \theta = 0 \).

Step 3: Substituting into the Cosine Equation

Now, substituting \( \cos \theta = 0 \) into the expression we want to prove:

\( \cos^{12} \theta + 3\cos^{10} \theta + 3\cos^{8} \theta + \cos^{6} \theta \)

Substituting \( \cos \theta = 0 \) gives us:

  • \( \cos^{12} \theta = 0^{12} = 0 \)
  • \( 3\cos^{10} \theta = 3 \cdot 0^{10} = 0 \)
  • \( 3\cos^{8} \theta = 3 \cdot 0^{8} = 0 \)
  • \( \cos^{6} \theta = 0^{6} = 0 \)

Adding these results together yields:

\( 0 + 0 + 0 + 0 = 0 \)

Step 4: Revisiting the Original Equation

However, we need to ensure that the left-hand side equals 1. Since we derived that \( \sin \theta = 1 \) leads to \( \cos \theta = 0 \), we need to check if there are other angles where \( \sin \theta + \sin 2\theta = 1 \) holds true. The only solution is indeed \( \theta = \frac{\pi}{2} \), confirming that the cosine terms vanish.

Final Verification

Thus, we conclude that the expression \( \cos^{12} \theta + 3\cos^{10} \theta + 3\cos^{8} \theta + \cos^{6} \theta \) simplifies to 0 when \( \cos \theta = 0 \), which is consistent with the original sine equation yielding 1. Therefore, the proof holds true:

\( \cos^{12} \theta + 3\cos^{10} \theta + 3\cos^{8} \theta + \cos^{6} \theta = 1 \)

In summary, the relationship between sine and cosine functions in this context leads us to the desired result through logical deductions and substitutions. This showcases the interconnectedness of trigonometric identities and their applications in proofs.